Sunday, 27 March 2011

Limits and Continuity

Limits are fundamental for both differential and integral calculus. The formal definition of a derivative involves a limit as does the definition of a definite integral.

The limit of a function(if it exists) for some x-value, a is the height  the function gets closer and closer to as x gets closer and closer to a from the left and the right. Lets take a look at what that even means.

The limit of the function f(x) = 3x + 1 as x approaches 2. When writing a limit we denote this as the following equation.

lim f(x) = lim 3x+1.
x->2         x->2

Now for such an easy limit we can plug in the number 2 and solve this limit. Plugging in the 2 we see.


lim f(x) = lim 3(2)+1  = 7
x->2         x->2


 That the limit is 7. So as x approaches 2 from the left and right side. The limit of this function is 7.

 Now your probably think well that's silly. Any function that's continuous you just plug in and solve for x. Now limits are important for functions with holes.

Definition of a Limit:

lim f(x) exists if and only if

x -> a

1. lim f(x) exists
     x->a- (a from the left side)

2. lim f(x) exists, and
    x->a+(a from the right side)

3. lim f(x) = lim f(x)
    x -> a-      x->a+

Number three is the most important.


A function with an infinite limit and vertical asymptotes.

f(x)  = (x+2)(x-5) / (x-3)(x+1) This function has a VA at x = 3, x = -1

So the lim f(x) = lim (3+2)(3-5) / (3-3)(3+1) =  infinity as x will never reach 0 thus it heads closer to 0
           x-> 3-      x->3-

for infinity.

From the right side the limit will be negative infinity. Thus we know by the limit definition that the limit does not exist for x approaches 3.


Definition of Continuity:

A function is continuous at a point x  = a if the following three conditions are satsified.

1.f(a) is defined
2.limf(x) exists and,
    x-> a
3. f(a) = lim f(x)
              x->a

Limits to Memorize:

lim c = c
x->a

lim 1/x = infinity
x-> 0+

lim 1/x = negative infinity
x-> 0-

lim 1/x = 0
x -> infinity(same for both - and + infinity)

lim sin x/x = 1
x->0

lim cos x - 1/x =0
x->0

lim (1+1/x)^x = e
x -> infinity


Plugging and Chugging Limits:

Any limit where it's continuous and straight forward.

lim (x^2 - 10) = -1
x-> 3

lim 10/x-5= 10/0  if you get an answer that has any numerator thats not zero divided by zero. The limit
x - > 5

does not exist.

Now in the below case if you get 0/0 you have a real limit problem.

lim (x^2 - 25) / (x - 5) = 0/0 which is undefined
x-> 5

undefined is not the limit. This is not the answer we are looking for. Four things we can do to find a limit that is undefined. Calculator, algebra, limit sandwhich, L'Hopitals rule.

I will only show the algebra and L'Hopitals rule. I will not explain L'Hopitals Rule though.

Using algebra to solve for 
lim (x^2-25)/(x-5) we can rewrite this by factoring (x^2 - 5) = (x-5)(x+5) knowing this we can
x-> 5

divide out the (x-5) which leaves us with the equation lim x+5 = 10
                                                                                       x->5

Using L'Hoptials Rule

lim (x^2-25)/(x-5) = lim d/dx(x^2 - 25) / d/dx(x-5) = lim 2x = 10.
x-> 5                        x->5                                             x->5




      





             

32 comments:

  1. wish I was as smart as you sir!

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  2. It's so complicated, math hates me lol

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  3. im so confused. ill need to come back to this

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  4. wish i payed attention in high school math class. lol.

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  5. Engineer here, this was a good review of limits.

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  6. Numbers...numbers everywhere...Thanks for sharing this tho!! Math is so not my thing!

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  7. This may be handy later... nice post!

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  8. that is crazy as hell, but awesome.

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  9. There's several equations here that I'm not familiar with.

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  10. Love your blog style! Keep up the great work!

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  11. oh god i am bad in such things

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  12. I'm actually proud of myself for understand some of that, yes!

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  13. Hmmm very helpful although hard :p I'll stick around

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  14. Beginning of Gr 12 calculus for me.

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  15. Trying to understand all this math, but my brains steaming :D

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  16. I've only learnt how to interpret this into graph form at school at the moment :( nothing useful.

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  17. hahah exams in a few weeks, i'm getting ready

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  18. reminds me a too lot at secondary school :d

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  19. A computer programing friend told me that everything can be boiled down to 1's and 0's.

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  20. Life can be boiled down to 1's and 0's

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  21. helpful for my major ;)

    supported!
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